python對時間序列處理時數(shù)據(jù)小數(shù)位數(shù)混亂
問題描述
想對時間序列進(jìn)行狀態(tài)劃分，時間序列最大值1.8，最小值-0.5，劃分為115個狀態(tài)區(qū)間，每個狀態(tài)區(qū)間寬度為0.02，把處于各狀態(tài)區(qū)間的值化成區(qū)間中間的值，寫了一段代碼，但是得到的值有的小數(shù)位數(shù)很奇怪，請大神幫忙解惑，謝謝
__author__ = ’Administrator’file = open(’yij.txt’,’r’)while 1: line = file.readline() a = line.split() m=0 b=[-0.5,-0.48,-0.46,-0.44,-0.42,-0.40,-0.38,-0.36,-0.34,-0.32,-0.30,-0.28,-0.26,-0.24,-0.22,-0.20,-0.18,-0.16,-0.14,-0.12,-0.10,-0.08,-0.06,-0.04,-0.02,0.00,0.02, 0.04,0.06,0.08,0.10,0.12,0.14,0.16,0.18,0.20,0.22,0.24,0.26,0.28,0.30,0.32,0.34,0.36,0.38,0.40,0.42,0.44,0.46,0.48,0.50,0.52,0.54,0.56,0.58,0.60,0.62,0.64, 0.66,0.68,0.70,0.72,0.74,0.76,0.78,0.80,0.82,0.84,0.86,0.88,0.90,0.92,0.94,0.96,0.98,1.00,1.02,1.04,1.06,1.08,1.10,1.12,1.14,1.16,1.18,1.20,1.22,1.24,1.26,1.28, 1.30,1.32,1.34,1.36,1.38,1.40,1.42,1.44,1.46,1.48,1.50,1.52,1.54,1.56,1.58,1.60,1.62,1.64,1.66,1.68,1.70,1.72,1.74,1.76,1.78,1.80] if line != ’’:file1 = open(’yij_state.txt’, ’a+’)for i in b: if i<float(a[0])<=i+0.02:file1.write('%.2fn' % (i+0.01)) if float(a[0])<=-0.5:file1.write('%.2fn' % (-0.49)) elif float(a[0])>1.8:file1.write('%.2fn' % (1.79))breakfile1.close else:breakfile.close
代碼已經(jīng)改正確了
問題解答
回答1：保留兩位小數(shù)就行了
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