android - rxjava2封裝統(tǒng)一取消注冊問題
問題描述
我在rxjava1中這么寫沒有問題的,在rxjava2中我應(yīng)該怎么寫
問題解答
回答1:mDisposables.add(mTasksRepository.createAuthorize(rBody) .observeOn(AndroidSchedulers.mainThread()) .subscribe(loginResponse -> {Timber.i('createAuthorizeSuccess'); }, throwable -> {Timber.e('createAuthorizeError'); }));
RxJava 2 features several base classes you can discover operators on:
io.reactivex.Flowable : 0..N flows, supporting Reactive-Streams and backpressure
io.reactivex.Observable: 0..N flows, no backpressure
io.reactivex.Single: a flow of exactly 1 item or an error
io.reactivex.Completable: a flow without items but only a completion or error signal
io.reactivex.Maybe: a flow with no items, exactly one item or an error
取消訂閱可以試試 RxLifecycle https://github.com/trello/RxL...,使用起來很方便。
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